That would still be an approximation, just of a different kind (a pixelated approximation).
Consider texturing a bitmap circle into a triangle (why bother with a square when QL_QUADS is not supported in OpenGL-ES), when the triangle is very close to the observer or at an angle close parallel to the Z axis, the texels near the camera can become quite blocky. Of course you can use a bigger bitmap. The question would then become what is less work for the GPU, shifting around a big texture, or rendering more vertexes? Regards, Keean. On Sep 2, 2:52 pm, Streets Of Boston <[email protected]> wrote: > Doesn't this give you an approximation of a circle? > > If you want a true circle, you could try to create a square with a > texture on top, where the texture is an image of a circle. > > On Sep 2, 3:41 am, Keean Schupke <[email protected]> wrote: > > > > > Hi, > > > Use a TRIANGLE_FAN and compute the coordinates to put in your array > > buffer or VBO using the formula: > > > x = cos r > > y = sin r > > > where r goes from 0 to 2*PI in whatever step size you like. This will > > give you an anti-clockwise circle. > > > Regards, > > Keean. > > > On Sep 2, 8:16 am, "Frank von Daak" <[email protected]> wrote: > > > > Hi! > > > > I'm new to openGL and I have done some first tests with drawing a > > > triangle... > > > Now I would like to draw a circle, which is filled with a texture, but I > > > have > > > no idea, how to do so. > > > Can someone of you give me a hint? > > > > Thank you very much! > > > Frank > > > > -- > > > Name: Frank von Daak > > > eMail: [email protected] > > > "Enjoy yourself - it's later than you think!"- Hide quoted text - > > > - Show quoted text - --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -~----------~----~----~----~------~----~------~--~---
