I too would like to know this. On Oct 23, 1:31 pm, junker37 <[email protected]> wrote: > I am wondering how to do this as well. Also, I can't seem to find > where this is documented. > > On Oct 19, 4:19 am, Viktor Bresan <[email protected]> wrote: > > > Hi all. > > > I would like to have ashapethat hasborderonly on 3 sides: top, > > left and right, i.e. I want bottom to beopen. How can I achieve that > > definingshapeinXML? > > > Currently I have a normal 4 sideborderusing the followingshapeXML > > definition: > > > <?xmlversion="1.0" encoding="utf-8"?> > > <shapexmlns:android="http://schemas.android.com/apk/res/android"; > > android:layout_width="fill_parent" > > android:layout_height="fill_parent" > > > > > > <solid android:color="#FFE8F0F8" > > /> > > > <stroke android:width="1dp" > > android:color="#808480" > > /> > > > <padding android:left="1dp" > > android:top="1dp" > > android:right="1dp" > > android:bottom="1dp" > > /> > > </shape> > > > Many thanks, Viktor.
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