On 9 April 2010 18:19, Gubatron <[email protected]> wrote:
> I suppose when you say FilePart, you mean this
>
> org.apache.commons.httpclient.methods.multipart.FilePart
>
> I'm thinking along these lines after looking at that API (I haven't
> tested this)
>
> final File theFile = new File("yourFileLargerThan2Mb.ext");
>
> //Implement your own PartSource to feed your File
> PartSource partSource = new PartSource() {
> //this should return a buffered reader... right?
> public InputStream createInputStream() {
> return BufferedInputStream (new FileInputStream(theFile));
> }
>
> //implement the other methods of the interface
> public String getFileName() {
> return theFile.getName();
> }
>
> public long getLength() {
> return theFile.length();// although this might be how much is
> left on the stream, not sure.
> }
>
> }
>
> FilePart part = FilePart(theFileName, partSource);
>
> then use your part on your multipart request.
>
Thanks. Constructing a FilePart from a File is actually as easy as this, I
think - but do you think your method would provide some advantage?
File temp_file = new File(Environment.getExternalStorageDirectory(),
"myfile.gif");
FilePart vFile = new FilePart("fileupload", temp_file);
As I say, this works for files of 50MB. The only reason I can't use it is
that I can't construct a File object from an Android content Uri. I have to
use an Android content Uri because that's what the video intent returns.
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