Select a fixed buffer size first.
Then start writing the byte array to a file. Once the file size reaches the
buffer size configured, copy that file to a temporary location (a temp
file). Then transfer this temp file to the web server. Once transferred
successfully, make sure to delete this temp file (by calling deleteOnExit()
) when the file was created.
To make this work properly, there have to be 2 threads at work - the thread
that is writing the byte array to a file and the thread that is doing the
heavy duty stuff in the background - copy to the temp file location and
finally upload it to a server etc. This heavy duty thread waits on a
condition (waits for the file to reach the buffer size configured to start
the transfer).
I hope this makes sense...just sharing my thoughts aloud.
Best Regards
Indodroid.
On Sat, Apr 10, 2010 at 12:19 AM, Anna Powell-Smith <
annapowellsm...@googlemail.com> wrote:
>
>
> On 9 April 2010 19:35, Anna Powell-Smith
> <annapowellsm...@googlemail.com>wrote:
>
>>
>>
>> On 9 April 2010 18:19, Gubatron <gubat...@gmail.com> wrote:
>>
>>> I suppose when you say FilePart, you mean this
>>>
>>> org.apache.commons.httpclient.methods.multipart.FilePart
>>>
>>> I'm thinking along these lines after looking at that API (I haven't
>>> tested this)
>>>
>>> final File theFile = new File("yourFileLargerThan2Mb.ext");
>>>
>>> //Implement your own PartSource to feed your File
>>> PartSource partSource = new PartSource() {
>>> //this should return a buffered reader... right?
>>> public InputStream createInputStream() {
>>> return BufferedInputStream (new FileInputStream(theFile));
>>> }
>>>
>>> //implement the other methods of the interface
>>> public String getFileName() {
>>> return theFile.getName();
>>> }
>>>
>>> public long getLength() {
>>> return theFile.length();// although this might be how much is
>>> left on the stream, not sure.
>>> }
>>>
>>> }
>>>
>>> FilePart part = FilePart(theFileName, partSource);
>>>
>>> then use your part on your multipart request.
>>>
>>
>> Thanks. Constructing a FilePart from a File is actually as easy as this, I
>> think - but do you think your method would provide some advantage?
>>
>> File temp_file = new File(Environment.getExternalStorageDirectory(),
>> "myfile.gif");
>> FilePart vFile = new FilePart("fileupload", temp_file);
>>
>> As I say, this works for files of 50MB. The only reason I can't use it is
>> that I can't construct a File object from an Android content Uri. I have to
>> use an Android content Uri because that's what the video intent returns.
>>
>
> Ah. If I could transform my content Uri into FileInputStream (will have to
> experiment) then I could use your method.
>
> I can convert a content Uri to an InputStream already, so it'll just be
> getting from an InputStream to a FileInputStream that might be the
> challenge. I'll experiment.
>
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