Hello Sendar
This helps , also array has name and description, is it possible to search
in both rather just in one name ?
On Thursday, July 25, 2019, Sander Elias <sanderel...@gmail.com> wrote:
> Hi Dev,
>
> Your search pipe expects an object with at least the property name in each
> row, and your sort expects an array that contains only strings. Make sure
> you have those in sync.
> I changed them a bit, so they now accept a property's name:
>
> @Pipe({name: "sort"})
> export class ArraySortPipe implements PipeTransform {
> transform(array: Array<string>, propName: string): Array<string> {
> return [...array.sort((a: any, b: any) => a[propName] < b[propName] ? -1 :
> 1)]
> }
> }
>
> @Pipe({ name: 'search' })
> export class SearchPipe implements PipeTransform {
> transform(value: any[], prop,term: string): any[] {
> return value.filter((x: any) => term === '' || x && x[prop] && x[prop].
> toLowerCase().includes(term.toLowerCase()))
> }
> }
>
> See it in action on stackblitz
> <https://stackblitz.com/edit/angular-fu1hkj>
>
> Regards
> Sander
>
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