Hi,
Im a newbie ANTLR user and I had a basic question about the AST construction
operator '^' caret,
When the AST construction operator '^' (caret) is used along with a normal
rule such as
condStatement : 'expression' ^ x=statement1 (y=statement2)? ;
The term 'expression' becomes the root for the tree and the next un-suffixed
element i.e $x becomes the first child and $y becomes the second child. This
can be rewritten as ^('expression' $x $y?).
However when the operator '^' is used along with a subrule such as
expr : x=INT ('+' ^ y=INT)* ;
The $x is chosen as the first child not the next unsuffixed element i.e $y.
For example input 1+2 is parsed as ^('+' 1 2) and not as ^('+' 2 1)
Am I missing something obvious or Is this the behaviour of the AST
construction operator ?
Any pointers would be greatly appreciated.
List: http://www.antlr.org/mailman/listinfo/antlr-interest
Unsubscribe:
http://www.antlr.org/mailman/options/antlr-interest/your-email-address
--
You received this message because you are subscribed to the Google Groups
"il-antlr-interest" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/il-antlr-interest?hl=en.
