My apologies for the previous mail.
There is a small correction, table 7.1 mentions that the next, & not first,
un-suffixed element becomes the first child of the root. This seems
in-consistent with the grammar rules mentioned in the earlier mail.
Regards,
Hitesh

On 8/10/10, Hitesh Shetty <[email protected]> wrote:
>
> Hello,
>
> First of all, Thank you Mr. Jim for your reply.
> The question was actuall sent in reference to the Definite ANTLR reference,
> table 7.1 found on page 176,  which mentions that the first non-suffixed
> element becomes the first child of the root of the subtree. This seemed
> in-consistent with the grammar rules mentioned in the earlier mail.
>
> What is your opinion about this.
>
> Regards,
> Hitesh
>
> On 8/9/10, Hitesh Shetty <[email protected]> wrote:
>>
>> Hi,
>>
>> Im a newbie ANTLR user and I had a basic question about the AST
>> construction operator '^' caret,
>> When the AST construction operator '^' (caret) is used along with a normal
>> rule such as
>>    condStatement : 'expression' ^ x=statement1 (y=statement2)? ;
>> The term 'expression' becomes the root for the tree and the next
>> un-suffixed element i.e $x becomes the first child and $y becomes the second
>> child. This can be rewritten as ^('expression' $x $y?).
>> However when the operator '^' is used along with a subrule such as
>>    expr : x=INT ('+' ^ y=INT)* ;
>> The $x is chosen as the first child not the next unsuffixed element i.e
>> $y. For example input 1+2 is parsed as ^('+' 1 2) and not as ^('+' 2 1)
>> Am I missing something obvious or Is this the behaviour of the AST
>> construction operator ?
>> Any pointers would be greatly appreciated.
>>
>>
>>
>
>

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