That was my first guess too but I doubt that that is the cause.
Without the space, I expect it to see the 15 (corresponding to
the ('0'..'9')+ part) and then look ahead and see that the next part must
start with a ':' followed by a number. Since it doesn't see a number (it
sees a '=') it should end the RULE_ABSTRACT_LITERAL. Then parsing can
continue and would start from the ':' to match the RULE_EQUALS and then
again the RULE_ABSTRACT_LITERAL.
Mark
On Fri, Jan 14, 2011 at 4:30 PM, Søren Kristiansen <[email protected]>wrote:
> Hi Mark,
> Without the space before ':=', 15: will match your
> RULE_ABSTRACT_LITERAL rule and then '=' can't be
> matchted.
>
> Regards
> Soren
>
> 2011/1/14 Mark Christiaens <[email protected]>
>
>> I have a small test grammar:
>>
>> grammar test_grammar;
>>
>> testrule : t*;
>> t: RULE_EQUALS | RULE_ABSTRACT_LITERAL | RULE_WS ;
>> RULE_EQUALS : ':=';
>> RULE_ABSTRACT_LITERAL : ('0'..'9')+ (':' ('0'..'9')+ ':')?;
>> RULE_WS : (' '|'\t')+;
>>
>>
>> When I debug this grammar (with ANTLRWorks 1.4.2 using ANLTR 3.3) I feed
>> it
>> the input (no spaces)
>>
>>
>> 15:=0
>>
>>
>> and it doesn't parse my input correctly. When I change the input to
>> (adding
>> space before ':=')
>>
>> 15 :=0
>>
>> it parses successfully. Any ideas what I'm missing here?
>>
>> Mark
>> --
>> <http://www.sigasi.com>
>>
>> Mark Christiaens, PhD
>> Expert Research Engineer
>> www.sigasi.com
>>
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>
--
<http://www.sigasi.com>
Mark Christiaens, PhD
Expert Research Engineer
www.sigasi.com
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