Am 16.01.2011 22:23, schrieb Mark Christiaens:
> I simplified my test case further. The grammar is now:
>
> grammar test_grammar;
>
> start : t*;
> t: ASSIGN | NUM ;
> ASSIGN : ':=';
> //NUM : '0';
> NUM : '0' ':0'?;
>
> I would expect this to be able to match the input
>
> 0:=0
>
> but it doesn't. Changing the definition of NUM to the commented version and
> the grammar does match the input.
some lookahead may help:
ASSIGN: (':=')=> ':=' ;
NUM: '0' ( (':0')=>':0' )?;
Michael
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