If you are talking integrer arithmetic then I would have been extremely surprised if there was any rounding. Truncation is the norm. 12/5 == 14/5 == 2
I tested this with an AL on 7 and it is indeed so. If we're dealing with reals there is also no rounding. (untested). This is how the hardware acts. On reals you simply make your calculation different. If you want to round on ints then you could also do a different calculation: ((($int1$ * 10) / $int2$) + 5) / 10. In this case, the results are rounded: 12/5 ==2 14/5 == 3. Cheers Ben Chernys _______________________________________________________________________________ UNSUBSCRIBE or access ARSlist Archives at www.arslist.org ARSlist:"Where the Answers Are"
