Re: [ASN.1] Question on XER encoding of SEQUENCE OF element types

[Rajul Gupta]

Hi Ed,   I think in your example you are referring "A" as defined type, correct ? "A" is CHOICE here, so it will encoded like ChoiceType. Look at clause 25.5 (Table 5).   Following are the XER encoding of the value notations.   value A ::= a : 1 XER Encoding (Look at clause 28.10) <A>   <a>1</a> </A>   If you have a value notation,   value B ::= {a : 1} XER Encoding (Look at clause 25.3 and 25.5) <B>   <a>1</a> </B>   Further, the encoding of "value" with two elements will be,   value B ::= {a : 1, b : TRUE} <B>   <a>1</a>   <b><true/></b> </B>   I hope this may help you.   Regards,   Rajul Gupta Oss Nokalva (www.oss.com) [EMAIL PROTECTED] 732 302 9669 (x137)   ----- Original Message ----- From: Ed Day To: [EMAIL PROTECTED] Sent: Tuesday, July 02, 2002 9:53 AM Subject: [ASN.1] Question on XER encoding of SEQUENCE OF element types Hi,   In looking at Clause 25 of the 2002 X.680 pre-release, I am unable to determine how an element of a SEQUENCE OF type is to be encoded when a defined type that references one of the ValueList case types is referenced.  For example:   A ::= CHOICE {    a INTEGER,    b BOOLEAN }   B ::= SEQUENCE OF A   Would a single element of choice a with value 1 be encoded as <A><a>1</a></A> or <a>1</a>?   25.6 through 25.8 talk about TaggedType, ConstrainedType, and SelectionType rules, but I see no mention of DefinedType.  Am I missing something?   Regards,   Ed Day Principal Engineer Objective Systems, Inc. [EMAIL PROTECTED] (484) 875-3020 (main) (610) 608-4930 (mobile) (610) 321-0361 (fax) (877) 307-6855 (toll-free)