Ja , das hat der form designer gemacht -----Urspr�ngliche Nachricht----- Von: Alexander Zeitler [mailto:[EMAIL PROTECTED] Gesendet: Montag, 02. Februar 2004 15:42 An: [EMAIL PROTECTED] Betreff: RE: [Asp.net] Aktives Schema
Hallo, > Sub BindData() > Dim strConn as string = > "server=YourServer;uid=UID;pwd=PWD;database=Northwind" > Dim sql as string = "Select EmployeeID, FirstName, LastName, > Title from Employees" > Dim conn as New SQLConnection(strConn) > Dim objDR as SQLDataReader > Dim Cmd as New SQLCommand(sql, conn) > conn.Open() > objDR=Cmd.ExecuteReader(system.data.CommandBehavior.CloseConnection) > MyDataGrid.DataSource = objDR ------>hier become ich den fehler! > MyDataGrid.DataBind() > conn.close > hast Du das DataGrid in der CodeBehind deklariert? also z.B. public System.Web.UI.WebControls.DataGrid MyDataGrid? Gruss Alex _______________________________________________ Asp.net mailing list [EMAIL PROTECTED] http://www.glengamoi.com/mailman/listinfo/asp.net _______________________________________________ Asp.net mailing list [EMAIL PROTECTED] http://www.glengamoi.com/mailman/listinfo/asp.net
