Micha fallowing along I know x in math represents the unknown and of course if its not declared I will get back an error so what is x representing in this equation?
Thanks for your help by the way, can I buy you a pizza? LOL Tony... ----- Original Message ----- From: Mischa Kroon To: [email protected] Sent: Wednesday, May 11, 2005 2:48 PM Subject: Re: [AspNetAnyQuestionIsOk] VB.net String maniplulation problem whoops didn't read the full message. here is where you go wrong i think :) > location = words1.IndexOf("_new") > > If location > 0 or not -1 then > location will give the location of the start of "_new" you want the next char not the position of the "_" then: newstring_withnum_tostr = words1.substr (location + x, 1) words1.replace (newstring_withnum_tostr, cint (newstring_withnum_tostr) + 1 ) check it: response.write (words1) ----- Original Message ----- From: "Tony Trapp" <[EMAIL PROTECTED]> To: <[email protected]> Sent: Wednesday, May 11, 2005 11:13 PM Subject: [AspNetAnyQuestionIsOk] VB.net String maniplulation problem > Hey guys here is what I want to do. > > Lets say I have a file name is my database my_pic_new1.jpg first off. > > Now I want to change this file name to make it a uniqe file name but > I need to do a few things to the string first. > > Is in the string _new is there then I want to see if a number is > there. > > If there is a number there I want to take that number and what ever > it is increment that number up by one make the file now > my_pic_new2.jpg > > and so on. > > I am not asking for someone to write the code for me but point me to > where I can gain viable info on how to make this hapeen or a small > code example. > > Here is my code at present, > > > Dim words1 as String = tmnescort_currentpic_small > > Dim location as Integer > Dim Counter as Integer > Dim newstr as Integer > Dim newstring_withnum as Integer > Dim countvar as Integer > Dim newstring_withnum_tostr > dim addnum as String > > Counter = 0 > location = words1.IndexOf("_new") > > If location > 0 or not -1 then > > newstring_withnum_tostr = instr(1, words1, "1") > > > newstr = System.Convert.ToInt16 > (newstring_withnum_tostr + 1) > newstring_withnum = newstr & Counter + 1 > addnum = System.Convert.ToString(newstring_withnum) > > str_msg.Visible = True > str_msg.Text = "This is the pic name in DB " & > tmnescort_currentpic_small & "<br><br>new string was found<br><br>" & > addnum & "<br><br>" > > else > > str_msg.Visible = True > str_msg.Text = "This is the pic name in DB " & > tmnescort_currentpic_small & "<br>new string was not found<br><br>" & > addnum & "<br><br>" > > end if > > > what I get back printed out is > > This is the pic name in DB my_pic_new1.jpg > > new string was found > > 161 << this is what happens after my string manipualtion I dont want > this. > > Can any please help me? > > Thanks, > > Tony... > > > > > > > Yahoo! Groups Links > > > > > > > > -- > No virus found in this incoming message. > Checked by AVG Anti-Virus. > Version: 7.0.308 / Virus Database: 266.11.8 - Release Date: 5/10/2005 > > ------------------------------------------------------------------------------ Yahoo! Groups Links a.. To visit your group on the web, go to: http://groups.yahoo.com/group/AspNetAnyQuestionIsOk/ b.. To unsubscribe from this group, send an email to: [EMAIL PROTECTED] c.. Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service. [Non-text portions of this message have been removed] Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/AspNetAnyQuestionIsOk/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
