opaqueice Wrote:
> Actually, the image looks fine. He's added a sin with frequency f=.5
> (in some units) and amplitude A=200 to a sin with f=1 and A=100, but
> with a phase (70 degrees?). As you say, this has zero DC offset, if by
> that we mean its time-averaged value, but it is asymmetric because of
> the phase.Yes, I see now, sorry. The statements accompanying the figure were
nevertheless not precisely right. Adding a second harmonic does not "by
definition" produce asymmetry: sin x + sin 2x is an odd ("symmetrical")
function. And even with the phase change, yes, the asymmetric function
has mean zero; I don't see any meaningful sense in which this can be
called "DC."
--
tom permutt
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