if plane is (n*m) sphere is (n*(m-2)+2) number of vertices. i am correct?
current away3d sphere can be described as a plane with the top and bottom row vertices merged into 1 vertex. thus losing some of triangle count. but i didnt quite understand what is your goal so i dont know how to help you more. maybe this? http://www.studiodynamics.net/uv/uv_editor_1.gif On Dec 10, 12:39 pm, Ghislain Flandin <[email protected]> wrote: > Hello everybody, > > I'm new in Away3D and i'd like to know something. > > Is there a formula to create a Sphere (segmentW number and SegmentH > number) taking into account a vertice number? > > I explain : > > I explode a Plane with segmentW = n and segmentH = m , so i have (n*m) > *2 triangles after exploding (thanks to the Explode class). > > Then i want to distribute all these triangles on a sphere, so i built > a Sphere and get the coordinates of each vertex of this sphere. > > The problem i have is that i want (if it's possible) to get the same > number of triangles ( from my exploded plane) as the vertice (from my > sphere). > > Is there a way to do that ? > > Thanks for your help ! > > Ghislain
