Basic Newbie Question - Endpoint

[Miller, Janet]

I'm trying to create my first web service using wsdl that was generated
from an outside source (remote wsdl).  The wsdl looks like the
following:

<wsdl:definitions xmlns:http="http://schemas.xmlsoap.org/wsdl/http/";
xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/";
xmlns:s="http://www.w3.org/2001/XMLSchema";
xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/";
xmlns:tns="http://Sirit/ETTM/";
xmlns:tm="http://microsoft.com/wsdl/mime/textMatching/";
xmlns:mime="http://schemas.xmlsoap.org/wsdl/mime/";
targetNamespace="http://Sirit/ETTM/";
xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/";>
  <wsdl:types>
    <s:schema elementFormDefault="qualified"
targetNamespace="http://Sirit/ETTM/";>
  .
  .
  .
  <wsdl:service name="TZCService">
    <documentation xmlns="http://schemas.xmlsoap.org/wsdl/";>External
Access Web Services for Hybrid Tolling</documentation>
    <wsdl:port name="TZCServiceSoap" binding="tns:TZCServiceSoap">
      <soap:address
location="http://localhost/ETTMServices/TZCService.asmx"; />
    </wsdl:port>
  </wsdl:service>

I ran wsdl2java and generated both the client and server stub and
skeleton code, added my implementation code, and modified the target url
in many places.  Would it be easier to just modify the original wsdl and
change the url to my localhost?

What do I change the soap:address location to?  Should it be
"http://localhost:8080/axis/TZCService";?  And should I change
"http://Sirit/ETTM/"; to "http://localhost:8080";?

Thanks for your help,

Jan