Your #2 isnt a *one-line solution. *Its multple statements joined as one. If that works, here's an improvement.
>>> tuple(x for x in a if not x%2), tuple(x for x in a if not x%3) ((4, 12), (9, 12, 15, 21)) -jeff On Wed, Jan 9, 2013 at 1:11 PM, vijay <vnbang2...@yahoo.com> wrote: > Hi, > I want to know if there is any other better way for improving below > list compression. I have to use list compression only to achieve it. > > say i have list a=[1, 4, 9, 12, 15, 21] expected result (4, 12), (9, > 12, 15, 21) > > few solutions are > 1) [filter(None, l) for l in zip(*[(x if x % 2 == 0 else None, x if x % > 3 == 0 else None) for x in a])] > 2) [y for y in a if bool(y%2==0)],[y for y in a if bool(y%3==0)] > > Any other better way to improve this. > > > With Thanks > Vijay > _______________________________________________ > BangPypers mailing list > BangPypers@python.org > http://mail.python.org/mailman/listinfo/bangpypers > _______________________________________________ BangPypers mailing list BangPypers@python.org http://mail.python.org/mailman/listinfo/bangpypers
