Thanks Anand. This look good to me.
________________________________ From: Anand Chitipothu <anandol...@gmail.com> To: vijay <vnbang2...@yahoo.com>; Bangalore Python Users Group - India <bangpypers@python.org> Sent: Wednesday, 9 January 2013 1:43 PM Subject: Re: [BangPypers] List compression imrpovement On Wed, Jan 9, 2013 at 1:11 PM, vijay <vnbang2...@yahoo.com> wrote: > Hi, > I want to know if there is any other better way for improving below list >compression. I have to use list compression only to achieve it. > > say i have list a=[1, 4, 9, 12, 15, 21] expected result (4, 12), (9, 12, >15, 21) > > few solutions are > 1) [filter(None, l) for l in zip(*[(x if x % 2 == 0 else None, x if x % 3 >== 0 else None) for x in a])] > 2) [y for y in a if bool(y%2==0)],[y for y in a if bool(y%3==0)] > > Any other better way to improve this. How about this? [[x for x in a if x%i == 0] for i in [2, 3]] Anand _______________________________________________ BangPypers mailing list BangPypers@python.org http://mail.python.org/mailman/listinfo/bangpypers
