grep search for \\[^,]+
and replace with nothing On Friday, November 13, 2020 at 8:27:05 AM UTC-5 Howard wrote: > I have a dataset with a number of lines of data like this one: > > *1956,ML,Don Newcombe\newcodo01,BRO,4.5,27,7,0,3.06,268.0,139* > > In each line, in its third entry (in the above it is *Don > Newcombe\newcodo01*) I want to remove everything from the backslash up to > but not including its ending comma, so for the above line the output would > be this: > > *1956,ML,Don Newcombe,BRO,4.5,27,7,0,3.06,268.0,139* > > How can I do that? > > Thanks, > Howard > > -- This is the BBEdit Talk public discussion group. If you have a feature request or need technical support, please email "[email protected]" rather than posting here. Follow @bbedit on Twitter: <https://twitter.com/bbedit> --- You received this message because you are subscribed to the Google Groups "BBEdit Talk" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/bbedit/64b905b8-2ffa-45ed-9bfa-3f49cb55ac89n%40googlegroups.com.
