Curio. Both suggested Search patterns will also "see" themselves and match in the three lines of text below. Why?
1956,ML,Don Newcombe\newcodo01,BRO,4.5,27,7,0,3.06,268.0,139 \\.*?, \\[^,]+ On Friday, November 13, 2020 at 6:33:34 AM UTC-8 Robin Beech wrote: > grep search for > > \\[^,]+ > > and replace with nothing > > > On Friday, November 13, 2020 at 8:27:05 AM UTC-5 Howard wrote: > >> I have a dataset with a number of lines of data like this one: >> >> *1956,ML,Don Newcombe\newcodo01,BRO,4.5,27,7,0,3.06,268.0,139* >> >> In each line, in its third entry (in the above it is *Don >> Newcombe\newcodo01*) I want to remove everything from the backslash up >> to but not including its ending comma, so for the above line the output >> would be this: >> >> *1956,ML,Don Newcombe,BRO,4.5,27,7,0,3.06,268.0,139* >> >> How can I do that? >> >> Thanks, >> Howard >> >> -- This is the BBEdit Talk public discussion group. If you have a feature request or need technical support, please email "[email protected]" rather than posting here. Follow @bbedit on Twitter: <https://twitter.com/bbedit> --- You received this message because you are subscribed to the Google Groups "BBEdit Talk" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/bbedit/d42c68f4-fc62-4d88-a11f-775f85d86ae4n%40googlegroups.com.
