On 6 Jun 2023, at 3:14, Otto Munters wrote:
> This formula does its job:
> Find: (?=(^.{120,130}))(^\n?.{61})
> Replace: \2\n
>
> I then repeat this formula with different values, from high to low.
> (?=(^.{120,130}))(^\n?.{61})
> (?=(^.{110,120}))(^\n?.{55})
> (?=(^.{100,110}))(^\n?.{50}
> )(?=(^.{90,100}))(^\n?.{45})
> (?=(^.{80,90}))(^\n?.{40})
> (?=(^.{70,80}))(^\n?.{35})
>
> Since there are many different files involved, it would be nice if this
> search and replace command could be done for the whole series at once. Is
> that even possible?
This is exactly the use case for a Text Factory. :-)
R.
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