Thank all for your kind help!
It was not difficult to make a textfactory doing this job.
I did have to enter the formula above many times in the textfactory with
different values to get the desired result.
The first part of the formula remained the same as in the series above, the
second part I had to repeat much more often. Each line with 10 different
values in the second part.
That way the lines of different lengths are neatly divided into two lines.
OM
Op dinsdag 6 juni 2023 om 15:46:00 UTC+2 schreef Rich Siegel:
> On 6 Jun 2023, at 3:14, Otto Munters wrote:
>
> > This formula does its job:
> > Find: (?=(^.{120,130}))(^\n?.{61})
> > Replace: \2\n
> >
> > I then repeat this formula with different values, from high to low.
> > (?=(^.{120,130}))(^\n?.{61})
> > (?=(^.{110,120}))(^\n?.{55})
> > (?=(^.{100,110}))(^\n?.{50}
> > )(?=(^.{90,100}))(^\n?.{45})
> > (?=(^.{80,90}))(^\n?.{40})
> > (?=(^.{70,80}))(^\n?.{35})
> >
> > Since there are many different files involved, it would be nice if this
> > search and replace command could be done for the whole series at once. Is
> > that even possible?
>
> This is exactly the use case for a Text Factory. :-)
>
> R.
>
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