On Monday 03 August 2009 22:58:30 Larry Finger wrote:
> Gábor states it the way the Broadcom routine is written. They have the
> flags divided into 3 16-bit values - high, middle, and low. The values
> are kept in arrays - one set is for the current band and the other is
> for both bands. When the routine is entered, the appropriate quantity
> is saved in a temporary, then the array value is maskset. Only when
> the resulting value changes is the shared memory location updated. The
> implication is that shared memory writes are expensive. Is that true?

No. I think it has other reasons.

-- 
Greetings, Michael.
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