On Mon, Aug 3, 2009 at 11:16 PM, Michael Buesch<[email protected]> wrote: > On Monday 03 August 2009 22:58:30 Larry Finger wrote: >> Gábor states it the way the Broadcom routine is written. They have the >> flags divided into 3 16-bit values - high, middle, and low. The values >> are kept in arrays - one set is for the current band and the other is >> for both bands. When the routine is entered, the appropriate quantity >> is saved in a temporary, then the array value is maskset. Only when >> the resulting value changes is the shared memory location updated. The >> implication is that shared memory writes are expensive. Is that true? > > No. I think it has other reasons. > > -- > Greetings, Michael. >
In that case, is the code correct: -- Vista: [V]iruses, [I]ntruders, [S]pyware, [T]rojans and [A]dware. :-) _______________________________________________ Bcm43xx-dev mailing list [email protected] https://lists.berlios.de/mailman/listinfo/bcm43xx-dev
