[OT] and/or operator

[Michael Fowler]

On Thu, Jun 07, 2001 at 06:39:32PM -0400, Travis Smith wrote:
> <snip src="Chas Owens">
> Either you or I (or maybe both us) have a really dirty mind.
> <snip>
> 
> Isn't that like:
>   (true != 0)

Nope, that's ($you || $I || ($you && $I)), which reduces to simply ($you ||
$I).

 
> You know, there's no and/or operator. In ksh you do have the |& - but that's
> something different.

There is an and/or operator, it's ||.  :)


Michael
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