On Apr 29, 4:57 am, shawnhco...@gmail.com (Shawn H Corey) wrote:
> Akhthar Parvez K wrote:
> > Hi,
>
> > The following line stores the first return value by the function Function1
> > to the variable $name:
>
> > my ($name) = @_[0] = &Function1 ($arg);
>
> > but this one doesn't work:
> > my ($name) = $_[0] = &Function1 ($arg);
>
> > Eventhough I've no issues to use the first one as long as it works well for
> > me, but I'm getting the following warning:
> > Scalar value @_[0] better written as $_[0]
>
> > I hate warnings, but how can I fix that? As I said, $_[0] doesn't work. Can
> > someone shed some light on this?
For a full explanation of the warning:
perl -Mdiagnostics your_script.pl
>
> my ( $name ) = () = Function1( $arg );
>
Um, that won't do what you think. The () just tosses all
the return arg's and $name remains undefined because
of the list context.
my($name) = () = Function1($arg); # $name stays undef
If $name were in scalar context though, you'd get a count
of the arg's returned and thrown away by ():
my $name = () = Function1($arg); # count of args to ();
A couple of other alternatives:
my ($name) = Function1($arg);
my $name = ( Function1($arg) )[0];
--
Charles DeRykus
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