On Thursday 29 Apr 2010, C.DeRykus wrote: > Um, that won't do what you think. The () just tosses all > the return arg's and $name remains undefined because > of the list context. > > my($name) = () = Function1($arg); # $name stays undef > > If $name were in scalar context though, you'd get a count > of the arg's returned and thrown away by (): > > my $name = () = Function1($arg); # count of args to (); > > A couple of other alternatives: > > my ($name) = Function1($arg); > my $name = ( Function1($arg) )[0];
Nice to see all these explanations coming in. Thanks Charles :-) -- Regards, Akhthar Parvez K http://Tips.SysAdminGUIDE.COM UNIX is basically a simple operating system, but you have to be a genius to understand the simplicity - Dennie Richie -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
