On 10-08-04 05:39 AM, Sooraj S wrote:
Hi,My code is accepting an option "version" as an integer. If it is less than 100, i need to add a zero in front of it so that i can do the further processing. Although this code is working, i am not sure that its the proper way. if ($version< 100) { # convert an integer-variable to string. $version = sprintf("0%d",$version); } I dont want to use something like my $str = sprintf("0%d",$version); I want to have it in the same variable "version".
Try: $version = sprintf( '%03d', $version ); See `perldoc -f sprinf` -- Just my 0.00000002 million dollars worth, Shawn Programming is as much about organization and communication as it is about coding. The secret to great software: Fail early & often. Eliminate software piracy: use only FLOSS. -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
