Hi,
Additional noob question: What would be wrong with
$version = '0'.$version;
?
LG,
Nora
> -----Ursprüngliche Nachricht-----
> Von: Shawn H Corey [mailto:shawnhco...@gmail.com]
> Gesendet: Donnerstag, 05. August 2010 01:58
> An: beginners@perl.org
> Betreff: Re: Is this perl statement valid?
>
> On 10-08-04 05:39 AM, Sooraj S wrote:
> > Hi,
> >
> > My code is accepting an option "version" as an integer. If it is
> less
> > than 100, i need to add a zero in front of it so that i can do the
> > further processing.
> >
> > Although this code is working, i am not sure that its the proper way.
> > if ($version< 100)
> > {
> > # convert an integer-variable to string.
> > $version = sprintf("0%d",$version);
> > }
> >
> > I dont want to use something like my $str = sprintf("0%d",$version);
> I
> > want to have it in the same variable "version".
> >
> >
>
> Try:
>
> $version = sprintf( '%03d', $version );
>
> See `perldoc -f sprinf`
>
>
> --
> Just my 0.00000002 million dollars worth,
> Shawn
>
> Programming is as much about organization and communication
> as it is about coding.
>
> The secret to great software: Fail early & often.
>
> Eliminate software piracy: use only FLOSS.
>
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