related question: I want to strip out any '*' symbols as well, and replace them with a zero. So, I changed my code to reflect:
$origFee =~ s/[%\*]/0/; It appears that it strips out the % successfully, but anywhere I have a '*' symbol just gets overlooked. Any thoughts? -----Original Message----- From: John W. Krahn [mailto:[EMAIL PROTECTED]] Sent: Friday, December 21, 2001 9:05 PM To: [EMAIL PROTECTED] Subject: Re: substitution Herb Martin wrote: > > > s/%//; # replaces any '%' signs in $_ with nothing > > > > but, I want to replace any '%' signs in > > $iAmAVariableHearMeRoar with nothing > > (Correct) Answer given by another poster: > >> $iAmAVariableHearMeRoar =~ s/%//; > > The original message did IMPLY there might be MULTIPLE > '%' characters (perhaps not together.) > > If THIS is the REAL request, try this: > > $iAmAVariableHearMeRoar =~ s/%//g; > > g = "globally" (or multiple patterns where found.) Or if you want to do it more efficiently (the string is really long.) $iAmAVariableHearMeRoar =~ tr/%//d; John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
