Frank McCollum wrote: > > From: John W. Krahn [mailto:[EMAIL PROTECTED]] > > > > Herb Martin wrote: > > > > > > > s/%//; # replaces any '%' signs in $_ with nothing > > > > > > > > but, I want to replace any '%' signs in > > > > $iAmAVariableHearMeRoar with nothing > > > > > > (Correct) Answer given by another poster: > > > >> $iAmAVariableHearMeRoar =~ s/%//; > > > > > > The original message did IMPLY there might be MULTIPLE > > > '%' characters (perhaps not together.) > > > > > > If THIS is the REAL request, try this: > > > > > > $iAmAVariableHearMeRoar =~ s/%//g; > > > > > > g = "globally" (or multiple patterns where found.) > > > > Or if you want to do it more efficiently (the string is really long.) > > > > $iAmAVariableHearMeRoar =~ tr/%//d; > > related question: I want to strip out any '*' symbols as well, and replace > them with a zero. So, I changed my code to reflect: > > $origFee =~ s/[%\*]/0/; > > It appears that it strips out the % successfully, but anywhere I have a '*' > symbol just gets overlooked. Any thoughts?
$origFee =~ tr/*%/0/d; John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
