On Apr 9, Nikola Janceski said:
>my bad... you are right... interesting... is this a special case where map
>return $1 instead of 1?
>or is it a special case where /(PATTERN)MOREPATTERN/ evaluates to $1 when
>true? (but why then no null elements?... interesting..
No; as my post stated, doing LIST = map BLOCK LIST; puts BLOCK in list
context. A regex in list context will return the parenthetical captures
if it succeeded, and () if it failed:
($first, $last) = "Jeffrey Pinyan" =~ /(\S+)\s+(\S+)/;
Thus, map { m!(.*)/\*! } LIST will return $1 or () for each element of the
LIST.
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
[ I'm looking for programming work. If you like my work, let me know. ]
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