Why are there still no empty elements in the returned array for the items
that didn't match the pattern?
@must == 2

I am just befuddled but this "paradox"

> -----Original Message-----
> From: Jeff 'japhy' Pinyan [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, April 09, 2002 4:27 PM
> To: Nikola Janceski
> Cc: '[EMAIL PROTECTED]'; 'Beginners (E-mail)'
> Subject: RE: rewrite without using two functions?
> 
> 
> On Apr 9, Nikola Janceski said:
> 
> >my bad... you are right... interesting... is this a special 
> case where map
> >return $1 instead of 1?
> >or is it a special case where /(PATTERN)MOREPATTERN/ 
> evaluates to $1 when
> >true? (but why then no null elements?... interesting..
> 
> No; as my post stated, doing LIST = map BLOCK LIST; puts BLOCK in list
> context.  A regex in list context will return the 
> parenthetical captures
> if it succeeded, and () if it failed:
> 
>   ($first, $last) = "Jeffrey Pinyan" =~ /(\S+)\s+(\S+)/;
> 
> Thus, map { m!(.*)/\*! } LIST will return $1 or () for each 
> element of the
> LIST.
> 
> -- 
> Jeff "japhy" Pinyan      [EMAIL PROTECTED]      
> http://www.pobox.com/~japhy/
> RPI Acacia brother #734   http://www.perlmonks.org/   
http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for?  <tenderpuss> why, yansliterate of course.
[  I'm looking for programming work.  If you like my work, let me know.  ]


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