actually it needed to be ($org=$1)=~s/,//g; Because $1 is read-only (regular expression variable). But your code gave me the clue I needed.
-----Original Message----- From: Jensen Kenneth B SrA AFPC/DPDMPQ [mailto:[EMAIL PROTECTED]] Sent: Friday, December 27, 2002 3:23 PM To: 'Paul Kraus'; 'Perl' Subject: RE: Why do these two statements generate different output? Yes ($org) = ($1 =~ s/,//g); Is the same as $1 =~ s/,//g; $org = $1; -----Original Message----- From: Paul Kraus [mailto:[EMAIL PROTECTED]] Sent: Friday, December 27, 2002 2:21 PM To: 'Paul Kraus'; 'Perl' Subject: RE: Why do these two statements generate different output? ok I was wrong. Its Friday so I am half alert :) the 17094. is actually the tail end of this error. Modification of a read-only value attempted at armonth.pl line 30, <AGING> line 17904. Are you able to make an assignment like this? > -----Original Message----- > From: Paul Kraus [mailto:[EMAIL PROTECTED]] > Sent: Friday, December 27, 2002 3:19 PM > To: Perl > Subject: Why do these two statements generate different output? > > > $1 from reg expr is equal to 2300,150.17 > > $org = $1; > $org=~s/,//g; > Generates 2300150.17. Which is correct. > > $org = $1 =~ s/,//g; > Generates 17904. > > Now if I am correct the binding =~ has precedence over =. So > it should generate the same output. > > Paul Kraus > Network Administrator > PEL Supply Company > 216.267.5775 Voice > 216-267-6176 Fax > www.pelsupply.com > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
