On Thursday 15 April 2004 11:22, Jayakumar Rajagopal wrote: > > $a=100; $b=200; > ($a=3 && $b=6 ) if ( 1 == 1 ); > print " $a $b \n"; > > Output : 6 6 > > OR my syntax is wrong ?
You have a precedence problem. Your expression evaluates as: $ perl -MO=Deparse,-p -e'($a=3 && $b=6 ) if ( 1 == 1 );' ($a = ($b = 6)); -e syntax OK You need to either add parentheses or use the lower precedence 'and' operator: ( ($a = 3) && ($b = 6) ) if ( 1 == 1 ); Or: ( $a = 3 and $b = 6 ) if ( 1 == 1 ); John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
