John W. Krahn wrote: > Or: > > ( $a = 3 and $b = 6 ) if ( 1 == 1 );
or if he intends both assignments to be made together: $a = 3, $b = 6 if 1 == 1; This will set $b to 6 even if $a is set to a false value, which the prior methods won't do. This may or may not be what the OP is after... -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
