First, always
use warnings;
use strict;
at the top of each program you write. Second, what are you trying to do
exactly? Third, some observations:
1) You use $j and $pos exactly one time. Why are they present?
2) You seem to be looping to 10 using $i. Why not instead use
for my $i(1 .. 10) { code here }
3) What are you trying to do with <LOGFILE>?
It seems to me that you are printing each item in @buffer, then printing the
next 10 lines of LOGFILE. Is this what you are trying to do? Are @buffer and
LOGFILE related at all?
Thanks,
ZO
"Sreedhar Kalkunte-Venkatachala" <[EMAIL PROTECTED]>
wrote...
Hi
Say I have program like this
If I Say print It prints each line. How to store the both output in one
string buffer ($previousLine and $var)
For example I have written this program
========================================
foreach $previousLine (@buffer)
{
$j++;
print "$previousLine";
}
$i = 0;
$pos = tell LOGFILE;
while(<LOGFILE>)
{
$i++;
if ($i > 10)
{
last;
}
$var = $_;
print $var;
}
========================================
Regards
Sreedhar
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