100| 1+ 10 ^&.x: i. 19
2 11 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
3!:0[ 1+ 10 ^&.x: i. 19
4
100| 1+ 10 ^&.x: i. 20
2 11 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0
3!:0[ 1+ 10 ^&.x: i. 20
8
/Erling
On 2017-10-09 20:19, Erling Hellenäs wrote:
a=: 1 + 10 ^&.x: i. 18
100|a
2 11 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
1 e.(=<:) @:<. a=: 1 + 10^i.18
0
100|a
2 11 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0
/Erling
On 2017-10-09 01:13, bill lam wrote:
1 e.(=<:) @:<. 10^i.10
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