(Note that the subject of the original message contained
a typo <. for >., though the text was correct.)

I don't see the logic. x+_.
is _. because if you don't know what _. is, you don't
know the result, even if x is _  .  But with _ >. _. 
you know the result, no matter what _. is: _ >. x
is _ for all x.  So _ would be a reasonable answer.

You said earlier that _. <: _  should produce 1,
which seems to conform to my argument above.  If
_. is recognized as less-or-equal _, I think it
needs to follow that _. >. _ is _    .

The case that got me into this _. mess was

1 2 3 _ I. _.

where I had a list that I thought I had terminated with a
high value, but I found that _. is higher yet.  It
would simplify analysis and description if _. were
consistently recognized as not being bigger than _   .

Henry Rich

> -----Original Message-----
> From: [EMAIL PROTECTED] 
> [mailto:[EMAIL PROTECTED] On Behalf Of Roger Hui
> Sent: Wednesday, February 06, 2008 10:45 PM
> To: Beta forum
> Subject: Re: [Jbeta] Another incompatibility: _ <. _.
> 
> The answer should be _. for the same reason that x+_. should be _. .
> That is, for all numeric atoms x, _. should be the answer for
> 
>    x  +  _.
>    x  >. _.
>    x  <. _.
>    _. +  x
>    _. >. x
>    _. <. x
> 
> 
> 
> ----- Original Message -----
> From: Henry Rich <[EMAIL PROTECTED]>
> Date: Wednesday, February 6, 2008 6:55
> Subject: [Jbeta] Another incompatibility: _ <. _.
> To: 'Beta forum' <[email protected]>
> 
> > I also just got bit by
> > 
> >    _ >. _.
> > _.
> > 
> > This gave _ in 601.  And in 602,
> > 
> >    _. >. _
> > _ 
> > 
> > 
> > I think both results should be _
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