Then how come grade down has _. the largest?

   z=._. __ _123.45 0 456.78 _
   z
_. __ _123.45 0 456.78 _
   /:~z
_. __ _123.45 0 456.78 _
   \:~z
_. _ 456.78 0 _123.45 __


On Feb 7, 2008 10:04 AM, Roger Hui <[EMAIL PROTECTED]> wrote:

> You are correct.  I was wrong when I said _ >. _. and _ <. _.
> should be _. ,  and the situation is different from x+_. .
> The difference is that J specifies a total array ordering,
> and in this ordering the sequence from smallest to greatest is:
>
> _. __ _123.45 0 456.78 _
>
> If you are going to have a TAO, obviously _. should be less
> than _ (infinity).  _. is specified to be less than __ (negative
> infinity) for to enable an algorithmic (implementation) advantage.
>
>
>
> ----- Original Message -----
> From: Henry Rich <[EMAIL PROTECTED]>
> Date: Thursday, February 7, 2008 5:14
> Subject: RE: [Jbeta] Another incompatibility: _ >. _.  WAS: _ <. _.
> To: 'Beta forum' <[email protected]>
>
>  > (Note that the subject of the original message contained
> > a typo <. for >., though the text was correct.)
> >
> > I don't see the logic. x+_.
> > is _. because if you don't know what _. is, you don't
> > know the result, even if x is _  .  But with _ >. _.
> > you know the result, no matter what _. is: _ >. x
> > is _ for all x.  So _ would be a reasonable answer.
> >
> > You said earlier that _. <: _  should produce 1,
> > which seems to conform to my argument above.  If
> > _. is recognized as less-or-equal _, I think it
> > needs to follow that _. >. _ is _    .
> >
> > The case that got me into this _. mess was
> >
> > 1 2 3 _ I. _.
> >
> > where I had a list that I thought I had terminated with a
> > high value, but I found that _. is higher yet.  It
> > would simplify analysis and description if _. were
> > consistently recognized as not being bigger than _   .
> >
> > Henry Rich
> >
> > > -----Original Message-----
> > > From: [EMAIL PROTECTED]
> > > [mailto:[EMAIL PROTECTED] On Behalf Of Roger Hui
> > > Sent: Wednesday, February 06, 2008 10:45 PM
> > > To: Beta forum
> > > Subject: Re: [Jbeta] Another incompatibility: _ <. _.
> > >
> > > The answer should be _. for the same reason that x+_. should
> > be _. .
> > > That is, for all numeric atoms x, _. should be the answer for
> > >
> > >    x  +  _.
> > >    x  >. _.
> > >    x  <. _.
> > >    _. +  x
> > >    _. >. x
> > >    _. <. x
> > >
> > >
> > >
> > > ----- Original Message -----
> > > From: Henry Rich <[EMAIL PROTECTED]>
> > > Date: Wednesday, February 6, 2008 6:55
> > > Subject: [Jbeta] Another incompatibility: _ <. _.
> > > To: 'Beta forum' <[email protected]>
> > >
> > > > I also just got bit by
> > > >
> > > >    _ >. _.
> > > > _.
> > > >
> > > > This gave _ in 601.  And in 602,
> > > >
> > > >    _. >. _
> > > > _
> > > >
> > > >
> > > > I think both results should be _
> ----------------------------------------------------------------------
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>
>
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