Le 03/11/2013 08:40, Timo Hanke a écrit :
> I think the communication would have to go the other way around. Trezor
> has to commit to a value First. Like this:
> Trezor picks random s and sends S=s*G to computer, keeping s secret.
> Computer picks random t and sends t to Trezor.  Trezor makes r := s+t
> its internal master private key with corresponding master public key
> R := (s+t)*G. Since R = S+t*G, the computer can verify the master
> public key. As you say, the computer can then store R and can later
> verify for each derived pubkey that it was indeed derived from R, hence
> from his own entropy t.

I'm not sure how this differs from what I wrote...

However, if this is how it works, then my question remains:
The computer has no proof to know that pubkeys derived through bip32's 
private derivations are derived from its own entropy...
This verification would only work for public (aka type2) derivations.

.. but maybe Trezor works in a different way? I think an explanation 
from slush would be needed.

> However, Trezor could not use straight bip32 out of the box. The
> chaincode would have to be something like SHA(R). And the seed (that
> gets translated to mnemonic) would be r itself, making it 256 bit
> instead of only 128 bit.
> If the longer seed is bearable then this is a good way to do it.
> One question remains: if you only write down the mnemonic how can you be
> sure that it is correct and corresponds to the secret in Trezor? You
> cannot verify that on paper. You would have to restore it on some
> device, eg another empty Trezor, and see if it brings up the same master
> pubkey. Right?
I guess you have to trust Trezor that it derives R from r

Android is increasing in popularity, but the open development platform that
developers love is also attractive to malware creators. Download this white
paper to learn more about secure code signing practices that can help keep
Android apps secure.
Bitcoin-development mailing list

Reply via email to