Randy McMurchy wrote: > Matthew Burgess wrote these words on 09/26/05 01:44 CST: > > >>In its short life, I believe tradition has this user set up as >>'messagebus' in group 'messagebus'. I know it doesn't answer the full >>question, for that I'm in vehement agreement with archaic - just put >>users that don't specifially need group membership in their own group. > > > Agreed on the "messagebus" user. However, no documentation I could > find shows anything about a gid. > > Consensus from the group though, seems that gid=uid is the most > proper solution. Thanks to everyone for their input so far. I'm > hoping that Bruce throws his two cents in as well, as I noticed > when he created the groups/users table recently, the PostgreSQL > user does not have a gid assigned to it. > > Perhaps this was because he was just going on what was in the book > and didn't want to make changes. I do notice that on Anduin, > gid=uid is the norm in almost all cases.
I too normally make uid==gid with the same names. This creates consistency. When I added the section "About System Users and Groups", I didn't analyze each section, but basically grepped for useradd and groupadd instructions and added those. I didn't notice the "users" group in the useradd instruction. It certainly wouldn't be hard to add a postgres group 41 and put a groupadd instruction into the postgresql instructions. That seems like the best alternative to me. Do you want me to do it? -- Bruce -- http://linuxfromscratch.org/mailman/listinfo/blfs-dev FAQ: http://www.linuxfromscratch.org/blfs/faq.html Unsubscribe: See the above information page
