Which fits the word "bandlength" better than my discussion, which was an
experiment in explaining that latency has a cost to someone who doesn't
know waht it means.
--dave
On 4/9/23 19:04, David Lang via Bloat wrote:
TCP ramps up it's speed fairly slowly, and backs off fairly
drastically when it is told (via ECN or a dropped packet) that it has
hit the limit. As a result, a single TCP session is not going to fully
utilize a connection. There are people who do large, high speed
transfers over long distances on a regular basis (think movie studios
sending uncompressed movie footage around the world for processing).
To fully utilize their bandwidth, they use protocols that involve lots
of connections operating in parallel
David Lang
On Sun, 9 Apr 2023, Dave Collier-Brown via Bloat wrote:
Date: Sun, 9 Apr 2023 16:06:54 -0400
From: Dave Collier-Brown via Bloat <bloat@lists.bufferbloat.net>
Reply-To: Dave Collier-Brown <dave.collier-br...@indexexchange.com>
To: bloat@lists.bufferbloat.net
Subject: Re: [Bloat] Hey, all, what about bandlength?
Consider a connection to my ISP as being an empty water-pipe, and I
only want to measure the flow from the waterworks to me. In this case
the waterworks is Rogers in Toronto, and the numbers come from me
measuring the link with the Waveform bufferbloat tool.
The ISP promises me 1 Gbit/s of water. OK, there is no such thing,
but you get the idea (;-))
Let's consider the no-latency case.
* The ISP turns on the tap, and it takes half an RTT to get to me,
one way. Let that be 1 millisecond, 0.001s of delay.
* Once the delay is over, I get (1.0s - 0.001s) * 1 Gbit/s = 0.999
Gb/s. The 0.999 seconds is transfer time, and that transfer is at
full speed of the pipe, so it adds up to 0.999 Gb/s
* That's pretty good.
Now let's consider the best possible case where there is latency, but
only one delay of 0.456s. That basically means that only one
transfer happens in the second, so there is only once change for
latency to hurt me.
* the one-way delay is still 0.001s, but there is also 0.231s of
latency, for a delay of 0.232s
* (1.0s - (0.001s + 0.231s) ) * 1 Gbit/s =
* 1.0s - 0.232s = 0.549s * 1 Gbit/s = 0.768 GB/s
* Cut by a quarter, by one packet's delay
What about the worst case?
* It's not worst, but a pretty common case is a busy link with
1500-byte packets
* One packet is 12,000 bits
* In one second we can transfer 1,000,000,000 bits /
12,000bits/packet = 83,333.3 packets
* Maybe that many delays, too?
* Fortunately, no
I personally observed 456.2 Mbit/s, about 54% of a gigabit at home,
so it's more like the latency cut my bandwidth in half
--dave
On 4/8/23 22:32, Michael Richardson via Bloat wrote:
Dave Collier-Brown
<dave.collier-br...@indexexchange.com><mailto:dave.collier-br...@indexexchange.com>
wrote:
>> Dave Collier-Brown via
Bloat<bloat@lists.bufferbloat.net><mailto:bloat@lists.bufferbloat.net>
wrote:
>> They he said "bandlength"
>>
>> > That sounded like an odd name, but the idea was cool:
>>
>> > If I have a bandwidth of 1 Mbit/S, but it takes 2 seconds to
deliver
>> 1 > Mbit, do I have a bandlength of only 1/2 Mbit/S?
>>
>> Is that because there is 2seconds of delay?
> Well, 2 seconds elapsed time, 1 of which is delay.
Ah, would that include the delay to ask for the data?
(A DNS request, or an HTTP GET)
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