On 07 Dec 2002 12:26:35 +0100, Gabriel Dos Reis <[EMAIL PROTECTED]> wrote:
>5.2.10/1: > The result of the expression reinterpret_cast<T>(v) is the result of > converting the expression v to type T. [...] Are you saying you really understand what that phrase means? Can you explain it, and say please what notion do you assume as "primitive" (e.g. "converting an expression)? >and converting a Foo* to void* is well-defined. I don't think you can say whether a conversion is well-defined or not in C++ without considering *how* it is done. Maybe these are minor points in the context of your reasoning. Sorry if that is the case, but I tend to stop reading long posts when I hit (what I think is) the first major problem. Genny. _______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost
