Palit, Nilanjan said: > No. In Perl (or C), "$x++" => use & then increment, whereas "++$x" => > increment & then use. Thus the expression will use the existing value of > x (1) to compute the value of y & then increment x itself.
Doh! I get it. Thanks for that one. observation: I've never used ++$x in a program. ever. interesting. _______________________________________________ Boston-pm mailing list [email protected] http://mail.pm.org/mailman/listinfo/boston-pm
