On Mon, 2005-03-07 at 11:59, Palit, Nilanjan wrote: > > From: John Macdonald [mailto:[EMAIL PROTECTED] > > Sent: Monday, March 07, 2005 12:50 PM > > > Precedence has nothing to do with it. The issue is how the > > tokenizer breaks the input sequence '+++' into operator tokens. > > Absolutely. The trickier version of the same question is when both sides > of the '+++' are variables: > > $y=$x+++$z > > That's when you need to know that parsing is done left to right
As far as I'm aware, that's still a tokenizer issue. You're not touching the parser until you figure out what tokens "+++" make up, and once you've determined that, the precedence no longer matters (i.e., there's only one way to interpret TOK<$x> TOK<++> TOK<+> TOK<$z>. Now, if the tokenizer were handing back TOK<$x> TOK<+> TOK<+> TOK<+> TOK<$z>, that would be a different matter, but it's not. Of course, Perl's parser and tokenizer are deeply incestuous, but that's the general idea. -- Aaron Sherman <[EMAIL PROTECTED]> Senior Systems Engineer and Toolsmith "It's the sound of a satellite saying, 'get me down!'" -Shriekback _______________________________________________ Boston-pm mailing list [email protected] http://mail.pm.org/mailman/listinfo/boston-pm
