> From: Ronn Blankenship <[EMAIL PROTECTED]> > > At 06:32 AM 12/19/01, "The Fool" wrote: > > >To much work. But there is a series, that would probably conform to such > >a set of equations. It is trivial figuring out the entire series. > > > Meaning "the work is left to the reader as an exercise."
I did it in high school many years ago, and it was much simpler than
solving, x^2 + cx + c = 0, problems.
x = 2-2/x (sqrt(2) +- sqrt((2 - 1)))
^^^^ = plus and minus (the number and it's inverse)
