E1 incident faces don't contain V. So, why do you consider it?
Am 20.06.2016 20:05 schrieb "Rakshika Bagavathy" <
rakshika.bagava...@gmail.com>:
> Daniel,
>
> You had asked how one line would intersect another. So i made a simple
> drawing, which i've attached here.
> Here, we need to get the closest non-crossing edge for vertex V. And when
> we are considering edge E1, the perpendicular line from V to E intersects
> the edges of triangles 1, 2, and 3. So, we get triangle 3, from it we move
> to triangle 2. And finally at triangle 1, the vertex is a corner. Hence, we
> can mark this edge as ineligible.
>
> When we are considering E2, since an ortho projection is not possible, we
> get the feature pair to be a vertex- V1. The triangle 4 does not contain
> the vertex V, hence it is eligible to be the closest edge.
>
> Regards,
> Rakshika.
>
>
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