Hi Mario,
In 3D space, rectangular to a vector you have a plane and the vector is a
normal vector of this plane. In this plane are all vectors which are
perpendicular to your first vector, i.e. the vectors which products with
your first vector are 0. This gives you a first equation with two
variables.
Next, you want to intersect the plane with a ray. I.e., one vector from
your plan has to be a multiple of the ray which gives you another equation.
However, there should be examples in the BRL-CAD source code for this.
E.g., the ray-trace of the half primitive is very similar to your problem.
There, the intersection of a plane, given by a normal vector and a point in
it, and a ray, given by a start point and a direction, will be computed.
I hope this helps.
Regards,
Daniel
I'm facing a wall. I need to find a perpendicular vector with the condition
that it will intersect a third vector.
Basically, I have the ray and a vector drawn from my current point to the
previous point.
I want the perpendicular bisector of that vector to cross my ray, so that I
can obtain the intersection between the bisector and the ray.
For that I need two things:
1) Obtain the perpendicular vector. in 3D there are infinite options, but
only one will cross the ray. How do I get the one I need?
2) Obtain the intersection point.
I browsed through vmath.h but I didn't find anything that could help me. Do
you know any macro that could be useful here?
Otherwise I will need to make some of my own for this! If so, any ideas on
how to approach it?
Mario.
------------------------------------------------------------------------------
Check out the vibrant tech community on one of the world's most
engaging tech sites, Slashdot.org! http://sdm.link/slashdot
_______________________________________________
BRL-CAD Developer mailing list
brlcad-devel@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/brlcad-devel
