yes last dimension of a must be = to first dimension of b but then
x←1 2 3 4 y←1 3 3 3 x+.=y works On Fri, 17 Mar 2017 17:29:24 +0100 Juergen Sauermann <juergen.sauerm...@t-online.de> wrote: > Hi, > > the number of columns in a must match the number of rows in b (or the other > way around, > I don't quite remember). > > Try: > > a+.=⍉b > 3 0 0 0 0 > 0 3 0 0 0 > 0 0 3 0 0 > 0 0 0 3 0 > 0 0 0 0 3 > > /// Jürgen > > > On 03/17/2017 05:17 PM, enz...@gmx.com wrote: > Hi > > what am i missing here? > > a←b←5 3⍴⍳8 > > a=b > > +/a=b > > a+.=b length error > > > >
